| Keyword | CPC | PCC | Volume | Score |
|---|---|---|---|---|
| current density formula with electric field | 0.9 | 0.2 | 563 | 18 |
| electric field density formula | 1.43 | 0.5 | 208 | 87 |
| current density from electric field | 1.25 | 0.3 | 900 | 10 |
| current density in terms of electric field | 0.82 | 0.4 | 2745 | 12 |
| current density and electric field | 1.91 | 0.8 | 2013 | 66 |
| current density in relation to electric field | 1.76 | 0.7 | 7334 | 95 |
| electric field energy density formula | 1.26 | 0.7 | 3847 | 28 |
| electric field density equation | 0.51 | 0.6 | 1253 | 21 |
| formula of current density | 0.62 | 0.3 | 4782 | 97 |
| current density formula in terms of current | 1.16 | 0.5 | 9827 | 93 |
| current density vs electric field | 1.84 | 0.7 | 7734 | 25 |
| dimensional formula of current density | 1.58 | 0.4 | 262 | 54 |
| what is current density formula | 1.6 | 0.3 | 1734 | 78 |
| equation for current density | 1.17 | 0.8 | 5262 | 48 |
| how to calculate current density | 1.72 | 0.1 | 4993 | 90 |
Yes, an electric current =does= produce an electric field. This is due to relativity, specifically the Lorentz Contraction.
Is there any relation between charge density and current density?follows that the current density is related to the charge density by (2). The velocity vis the velocity of the charge. charge is set into motion depends on the physical situation. The charge might be suspended in or on an insulating material which is itself in motion. In that case, the velocity would also be that of
Does an electric field have direction or magnitude?The magnitude and the direction of the electric field can be determined by the Coulomb force F on the test charge q. If the field is created by a positive charge, the electric field will be in radially outward direction and if the field is created by negative charge, the electric field will be in radially inwards direction.
What is the strength and direction of an electric field?The field between the plates is uniform, due to the electric field having the same magnitude and direction between the plates. The electric field strength can be calculated by: E= V/d . where V is the potential difference between the plates and d is the distance separating the plates. This electric field strength applies to any charged object no matter where it is inbetween the plates. E may also have the units volt per metre (Vm^-1). Field Factors:
